四川大学C语言2004q真题_跨考网
a的|?span lang="EN-US">a,b 均ؓ(f) int ,每个表达式运到a=2,b=3?span lang="EN-US">(5?span lang="EN-US">)
(1) a+=b*5
//a=a+b*5,?span lang="EN-US">17
(2) a=b++
//a=3
(3) a%=(a%=b)
//l果?span lang="EN-US">0
(4) a=a>b&&b>a||a
//>的优先高(sh)&&?span lang="EN-US">||原式理解?span lang="EN-US">(a>b)&&(b>a)||a
&&q算W高?sh)?span lang="EN-US">||,原式理解?span lang="EN-US">((a>b)&&(b>a))||a,因ؓ(f)agؓ(f)2Q结果ؓ(f)1真。或q算是有一?span lang="EN-US">1
(5) a=!b<A&&!A<B< p>
//!的运符最高,<其次Q?span lang="EN-US">&&最原式理解ؓ(f)((!b)<A)&&((!A)<B))l果?span lang="EN-US">1< p>
(10?span lang="EN-US">)
include ?span lang="EN-US">stdio.h?span lang="EN-US">
struct node /*有向囄节点cd*/
{ int key;
struct node *left,*right,*up,*down;
;
int main (int argc ,char * argv [])
{ int i;
struct node nodes[5];
for( i=0;i<5;i++)
{ nodes [i].key=i;
nodes [i].left=NULL;
nodes [i].right=NULL;
nodes [i].up=NULL;
nodes [i].down=NULL;
nodes [0].left=nodes+1;
nodes [1].left=nodes;
nodes [1].up=nodes+2;
nodes [2].down=nodes+3;
nodes [3].right=nodes+4;
nodes [4].up=nodes;
nodes [4].down=nodes+1;
return 0;
0
4
2
2
3
(10?span lang="EN-US">)
int sameChar sAT SamePos (char *s1,char *s2);
(串结束符‘\0?/span>不比?span lang="EN-US">)?span lang="EN-US">
s1="abc",s2="Abc",则返回gؓ(f)2?span lang="EN-US">
int sameCharAtSame Pos (char *s1,char *s2)
{
int counter =0;
while (*sl && *s2)
{
if (*s1 == *s2)
counter ++;
s1++;
s2++;
return counter;
(15?span lang="EN-US">)
AQ?span lang="EN-US">CQ?span lang="EN-US">GQ?span lang="EN-US">U四个字符l成Q如下所C:(x)
ACUGCCCAUGAAAAACUUUUGACAC
“AUG?/span>后开始,遇到“UGA?/span>l束(不包?span lang="EN-US">“AUG?/span>?span lang="EN-US">“UGA?/span>?span lang="EN-US">)如上面的~码串需解码的有效子串ؓ(f)Q?span lang="EN-US">
AAAAACUUU
3个字W?span lang="EN-US">(?span lang="EN-US">“AAA?/span>Q?span lang="EN-US">“CGA?作ؓ(f)一个密码子(可以保证Q有效子串的长度一定ؓ(f)3的整数倍?span lang="EN-US">)可能的密码子(62U?span lang="EN-US">)?qing)相应码g如下形式攑֜~码文gcode.txt?span lang="EN-US">(按密码子字典序排?span lang="EN-US">);
AAA K
AAC N
………?p>
UUU F
CE序对存攑֜文g中的Ҏ(gu)字符串解码,在屏q输?gu)码串。如Q?span lang="EN-US">KNF
KNE
1、编码文?span lang="EN-US">code.txt攑֜c盘根目录?span lang="EN-US">;
2、要解码的特D字W串以文件Ş式存放,其串长不过1024字符;
3、你~写的程序应能处理命令参敎ͼ指定要解码的字符串文?span lang="EN-US">;
4、程序中可以使用C语言的标准库函数Q不需要写出头文g;
5、程序中应有必有的注释?span lang="EN-US">
#include ?span lang="EN-US">stdio.h?span lang="EN-US">
#include ?span lang="EN-US">string.h?span lang="EN-US">
struct
{
char name[4];
char code;
table [62];
int main (int argc,char *argv [ ])
{
FILE *codeB file=NULL, *string file =NULL;
char string [1024+2],buffer[4],*p,*end ;
int I;
/* (g)查命令行参数*/
if (argc<=1)
/*打开~码文g以及(qing)待解码文?span lang="EN-US">*/
codeB file=fopen ("c:\\code. txt","r");
string file =fopen (argv[1],"r");
if (code_file= = NULL | | string_file = =NULL)
return 1;
/* ȝ码文Ӟ结果记入表?span lang="EN-US"> */
for (i=0; i<62; i++)
{
fscanf(code_file, "%s %c\n", tabie[i], name, &table[i].code);
}
/*d解码文g内容?span lang="EN-US">string?span lang="EN-US"> */
fgets (string, sizeof (string), string_file);
/* 扫描有效子串?span lang="EN-US"> */
p= strstr(string, "AUG");
end = strstr (p + 3 , "UGA");
/*L效子Ԍ查表输出解码字符Q直到子串尾 */
for (p+=3; p
{
for (i=0; i<3; i++)
{
buffer [i] = p [i];
}
buffer [i] ='\0';
for (i=0; i<62; i++)
{
if (strcmp (buffer, table [i].name)) = = 0)
{
printf("%c", table[i]. code);
break;
}
}
}
/* 关闭~码文g以及(qing)待解码文?span lang="EN-US"> */
fclose (code_file);
fclose (string_file);
return 0;
}
(tng)
2022考研初复试已l接q尾壎ͼ考研学子全面q入2023届备?/b>Q跨考ؓ(f)23考研的考生准备?0大课包全E准备、全q复?fn)备考计划、目标院校专业辅对{全真复试模拟练?fn)和全程针对性指|2023考研的小伙伴针也已经开始择校和复习(fn)?jin),跨考考研畅学5.0版本全新升Q无Z在校在家都可以更自如的完成你的考研复习(fn)Q?/a>暑假集训?/span>带来?jin)院校专业初步选择Q明方向;考研备考全q规划,核心(j)知识点入门;个性化制定备考方案,助你赢在赯U,早出发一点离成功更q一点!
点击右侧咨询?/strong>直接前往?jin)解更?/strong>
考研院校专业选择和考研复习(fn)计划 | |||
2023备考学?/td> | 2023U上U下随时学习(fn) | 34所自划UK校考研复试分数U汇?/td> | |
2022考研复试最全信息整?/a> | 全国各招生院校考研复试分数U汇?/a> | ||
2023全日制封闭训l?/span> | 全国各招生院校考研调剂信息汇?/a> | ||
2023考研先知 | 考研考试U目有哪些? | 如何正确看待考研分数U? | |
不同院校相同专业如何选择更适合自己?/a> | 从就业说考研如何择专业? | ||
手把手教你如何选专业? | 高校研究生教育各学科门类排行?/a> |
相关推荐
跨考考研评
班型 | 定向班型 | 开班时?/td> | 高定?/td> | 标准?/td> | 评介绍 | 咨询 |
U季集训 | 冲刺?/td> | 9.10-12.20 | 168000 | 24800?/td> | 班面授+专业??+专业译֮向辅?协议加强评(高定?+专属规划{疑(高定?+_化答?复试资源(高定?+复试译(高定?+复试指导(高定?+复试班主?v1服务(高定?+复试面授密训(高定?+复试1v1(高定? | |
2023集训畅学 | 非定向(政英?数政qQ?/td> | 每月20?/td> | 22800?协议? | 13800?/td> | 先行阶在U课E?基础阶在U课E?强化阶在U课E?真题阶在U课E?冲刺阶在U课E?专业NҎ(gu)一对一评+班主dE督学服?全程规划体系+全程试体系+全程_化答?择校择专业能力定位体p?全年关键环节指导体系+初试加强?初试专属服务+复试全科标准班服?/td> |